The Axiom of Completeness (Part 2)
In the previous handout, we stated the following axiom:
Axiom 3: Every nonempty subset of $\mathbb{R}$ that is bounded above has a least upper bound in $\mathbb{R}$.
In this handout, we will explore Axiom 3 in detail. Let us begin with some important definitions.
Definition: Bounded Above and Below
A set $A\subseteq\mathbb{R}$ is bounded above if there exists $b\in\mathbb{R}$ such that
$$a \le b \text{ for all } a \in A.$$Such a number $b$ is called an for $A$.
A set $A\subseteq\mathbb{R}$ is bounded below if there exists $\ell\in\mathbb{R}$ such that
$$\ell \le a \text{ for all } a \in A.$$Such a number $\ell$ is called a for $A$.
Exercise
For each set below, complete the table.
| Set | Bounded Above? | Bounded Below? | One Upper Bound | One Lower Bound |
|---|---|---|---|---|
| (i) $A=(0,1)$ | ||||
| (ii) $B=\{x\in\mathbb{R}:x^2<4\}$ | ||||
| (iii) $C=\{x\in\mathbb{R}:x\ge 3\}$ | ||||
| (iv) $D=\left\{\frac{1}{n}:n\in\mathbb{N}\right\}$ | ||||
| (v) $E=\{x\in\mathbb{R}:x<5\}$ |
Definition: Least Upper Bound (Supremum)
A real number $s$ is the least upper bound or supremum of $A$ (written $s=\sup A$) if:
- $s$ is an upper bound for $A$: for all $a \in A$, $a \le s$.
- $s$ is the least such bound: if $b$ is any upper bound for $A$, then $s \le b$.
A real number $\ell$ is the greatest lower bound or infimum of $A$ (written $\ell=\inf A$) if:
- $\ell$ is a lower bound for $A$: for all $a \in A$, $\ell \le a$.
- $\ell$ is the greatest such bound: if $m$ is any lower bound for $A$, then $m \le \ell$.
Exercise: Uniqueness of Supremum
Let $A\subseteq\mathbb{R}$ be a nonempty set that is bounded above. Suppose $s_1$ and $s_2$ are both supremums of $A$. Prove that $s_1 = s_2$.
Note
The supremum of a set .
- If a set is , then it has no supremum (e.g., $\mathbb{N}$).
- The empty set has supremum. By convention, one sometimes writes $\sup\varnothing=-\infty$, but this is not a real number and is outside our definition.
Exercise: Computing Supremum and Infimum
For each set below, determine $\sup A$ and $\inf A$ (if they exist) and whether they belong to the set.
- $A=(0,1)$
- $C=\{x\in\mathbb{R}:x\ge 3\}$
- $D=\{x\in\mathbb{R}:x<5\}$
Reflection
Give an example from the list above where:
- the supremum exists but does not belong to the set:
- the infimum exists but does not belong to the set:
- neither the supremum nor the infimum belongs to the set:
Note: Maximum and Minimum
In general, $\sup A$ and $\inf A$ need not belong to the set $A$.
- If $\sup A\in A$, then $\sup A$ is called the maximum of $A$, and we write $\max A=\sup A$.
- If $\inf A\in A$, then $\inf A$ is called the minimum of $A$, and we write $\min A=\inf A$.
Proposition
Let $A\subseteq\mathbb{R}$ be nonempty and bounded above, and assume $s$ is an upper bound for $A$. Then $s=\sup A$ if and only if:
For every $\varepsilon>0$, there exists $a\in A$ such that $s - \varepsilon < a \le s$.
Visually
For any $\varepsilon > 0$, the interval $(s-\varepsilon, s]$ must contain at least one point from $A$.
Takeaway: No matter how small $\varepsilon$ is, $A$ must come within $\varepsilon$ of $s$ from below.
← Back to MATH 4630