Department of Mathematics & Statistics, Kenyon College — Research Talk

Projections in the Combination of Operators of Finite Orders Contributed Talk

Speaker Priyadarshi Dey
Venue AMS Special Session on New Faces in Operator Theory, JMM 2024, San Francisco, CA
Date January 2024
Note The open question posed here was resolved in arXiv:2512.22497 (2025)

Abstract

This talk investigates when a linear combination of powers of an $n$-potent operator $T$ (satisfying $T^n = T$) yields a projection. Starting from classical examples of projections as averages of isometric reflections, we develop the theory of "basic projections" — the fundamental building blocks — and enumerate all projections in $\operatorname{span}\{T, T^2, \ldots, T^{n-1}\}$ for small values of $n$. The talk concludes with an open question that was subsequently resolved in joint work with Easley and Monika (arXiv:2512.22497, 2025).

Motivation: Projections and Isometries

Projections and isometries are central objects in functional analysis for complementary reasons:

Definitions

Definition — Isometry

A linear map $T \colon X \to Y$ between normed spaces is an isometry if $\|Tx\| = \|x\|$ for every $x \in X$.

Definition — Projection and Reflection

A bounded operator $P \colon X \to X$ is a projection if $P^2 = P$.

A bounded operator $R \colon X \to X$ is a reflection if $R^2 = I$.

Projections as Averages of Reflections

Example — Finite Dimensional

On $\mathbb{R}^3$ with $\|\cdot\|_\infty$, define $R(x_1,x_2,x_3) = (x_2,x_1,x_3)$. Then $R^2 = I$ and $R$ is an isometry. The average $$P = \tfrac{1}{2}(I+R) \colon (x_1,x_2,x_3) \mapsto \tfrac{1}{2}(x_1+x_2,\, x_1+x_2,\, 2x_3)$$ is a projection.

Example — Infinite Dimensional

On $C[0,1]$, define $Rf(t) = f(1-t)$. Then $R^2 = I$ and $R$ is an isometry. The average $$P(f)(t) = \tfrac{1}{2}(f(t) + f(1-t))$$ is a projection.

General principle: If $R$ is an isometric reflection, then $P = \frac{1}{2}(I+R)$ is a projection.

The Converse Fails

Not every projection arises as $\frac{1}{2}(I+R)$. On $\mathbb{R}^3$ with $\|\cdot\|_\infty$, the projection $P(x_1,x_2,x_3) = (x_1+x_2, 0, x_3)$ would require $R(x_1,x_2,x_3) = (x_1+2x_2,-x_2,x_3)$, which is not an isometry.

Projections in the Convex Hull of Periodic Operators

Theorem — Botelho, Dey, Easley (JMAA, 2023)

For two isometries $T_0, T_1$ and positive $\lambda_0, \lambda_1$ with $\lambda_0 + \lambda_1 = 1$: if $Q = \lambda_0 T_0 + \lambda_1 T_1$ is a projection ($Q \neq I$), then $\lambda_0 = \lambda_1 = \frac{1}{2}$.

Theorem — Botelho, Dey, Easley (JMAA, 2023)

For $T^n = I$ and positive $\lambda_0, \ldots, \lambda_{n-1}$ summing to $1$: if $Q = \lambda_0 I + \lambda_1 T + \cdots + \lambda_{n-1} T^{n-1}$ is a projection, then $\lambda_0 = \cdots = \lambda_{n-1} = \dfrac{1}{n}$.

The $n$-Potent Problem: Basic Projections

Definition — $n$-Potent Operator

An operator $T$ is $n$-potent if $T^n = T$.

Examples: projections ($n=2$), tripotents ($n=3$), periodic operators $T^m=I$ ($n=m+1$).

Definition — Basic Projection

Let $T^{k+1} = T$ and $\lambda$ be a $k$-th root of unity. The projection $$Q_\lambda = \frac{1}{k}\sum_{i=1}^{k} \lambda^{-i} T^i$$ is called a basic projection.

Classification for small $n$

$n=2$ ($T^2 = T$): $Q = a_1 T$ is a projection $\Leftrightarrow$ $a_1 \in \{0,1\}$. Only projections: $0$ and $T$.

$n=3$ ($T^3 = T$): $Q = a_1 T + a_2 T^2$ is a projection $\Leftrightarrow$ $Q \in \left\{0,\; \dfrac{T+T^2}{2},\; \dfrac{-T+T^2}{2},\; T^2\right\}$.

Complete List for $n=4$ ($T^4=T$, $\omega = \frac{-1+\sqrt{3}i}{2}$)
#ExpressionType
1$0$trivial
2$\frac{1}{3}(T+T^2+T^3)$basic
3$\frac{1}{3}(\omega T+\omega^2 T^2+T^3)$basic
4$\frac{1}{3}(\omega^2 T+\omega T^2+T^3)$basic
5$\alpha T+\beta T^2+\frac{2}{3}T^3$#2+#3
6$\beta T+\alpha T^2+\frac{2}{3}T^3$#2+#4
7$\frac{1}{3}(-T-T^2+2T^3)$#3+#4
8$T^3$sum of all basic

where $\alpha = \frac{1+\sqrt{3}i}{6}$, $\beta = \frac{1-\sqrt{3}i}{6}$, $\omega = \frac{-1+\sqrt{3}i}{2}$. Exactly $2^3 = 8$ projections.

The Open Question and Its Resolution

Open Question (posed in this talk)

For an $n$-potent operator $T$, is it possible to classify all projections in $\operatorname{span}\{T, T^2, \ldots, T^{n-1}\}$ via the basic projections?

Resolved — Dey, Easley, Monika (arXiv:2512.22497, 2025)

Yes. Every projection in $\operatorname{comb}(T)$ is uniquely a sum $P_S = \sum_{\lambda \in S} P_{\{\lambda\}}$ of Riesz projections indexed by a subset $S \subseteq \sigma(T) \setminus \{0\}$. The full family forms a Boolean algebra with exactly $2^{|\sigma_0(T)|}$ elements — consistent with the count of $8 = 2^3$ for $n=4$ above.

arXiv:2512.22497 [math.FA]

References